BBireddy192192 (Community Member) asked a question.
I have used uploadfile.do service. But when passing file as argument getting 500 error.
Please see below URL which is calling.
please help me.
Exception in thread "main" java.lang.RuntimeException: Exception while calling URL:https://analysiscenter.veracode.com/api/5.0/uploadfile.do?app_id=[app_id value]&&file=@[file path value]&&sandbox_id=[sanbox_id value]
at com.veracode.WebApiCall3.callURL(WebApiCall3.java:138)
at com.veracode.WebApiCall3.uploadFile(WebApiCall3.java:57)
at com.veracode.WebApiCall3.main(WebApiCall3.java:24)
Caused by: java.io.IOException: Server returned HTTP response code: 500 for URL: https://analysiscenter.veracode.com/api/5.0/uploadfile.do?app_id=188973&&file=@C:/Bharath/Test.jar&&sandbox_id=562188
at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source)
at com.veracode.WebApiCall3.callURL(WebApiCall3.java:123)
... 2 more
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Hello
The '@filename' part in our documentation is specific to cURL - this causes data to be sent with application/x-www-form-urlencoded content type.
As you are using Java, I would recommend you look into our wrapper, which can be used as a library or a standalone application from the command line. The wrapper takes care of correctly uploading files, amongst other things. You can find more detail here: https://help.veracode.com/r/c_about_wrappers
If you prefer your own implementation, you would need to encode the data in a similar manner to cURL. I would suggest invoking the API from cURL with verbose mode (-v) and seeing how it's handled there. You can then implement it in a similar manner.
Alaur